document.write( "Question 368336: A mechanic has some 30% antifreeze solution and some 50% solution. How many liters of each should be used to get 50 liters of a 46% solution? Solve by using determinants.\r
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Algebra.Com's Answer #262528 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi,
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document.write( "Let x represent the total amount of the 50% solution.  
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document.write( "Then (50L - x) would be the amount of 30% solution
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document.write( "Question states***
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document.write( ".50x + .30(50L - x) = .46*50L
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document.write( "solving for x
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document.write( ".20x = .16*50L
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document.write( "x = 40L of the 50% solution and 10L of the 30% solution\r
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document.write( "checking our answer
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document.write( "20 + 3 = 23 \n" );
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