document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40848>Question 40848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I add these rational expressions? 2 / y - 1 + 2 / y + 1 ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26248 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 / (y - 1) + 2 / (y + 1)<BR>\n" );
document.write( "For this, you first determine the lowest common denominator and then multiply each fraction in such a way that the denominators becomes that LCD...in this case, the LCD is (y - 1)(y + 1)...<BR>\n" );
document.write( "We multiply the first by (y + 1) / (y + 1)<BR>\n" );
document.write( "and the second by (y - 1) / (y - 1) and get<BR>\n" );
document.write( "2(y + 1) / (y - 1)(y + 1) + 2(y - 1) / (y - 1)(y + 1) =<BR>\n" );
document.write( "[2(y + 1) + 2(y - 1)] / (y - 1)(y + 1) =<BR>\n" );
document.write( "4y / (y - 1)(y + 1)<BR>\n" );
document.write( "The easiest way is to apply the criss-cross method...<BR>\n" );
document.write( "A/B + C/D = (AD + BC) / BD </SPAN>\n" );
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