document.write( "Question 368302: Can you help me out with this!!!
\n" ); document.write( "if x=1 is the day tickets go on sale.
\n" ); document.write( "Tickets= -0.4^2+20x+122.1\r
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\n" ); document.write( "\n" ); document.write( "b. What is the number of tickets sold on the 10th day? The 20th day? The 40th day? The 50th day?
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Algebra.Com's Answer #262477 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"T%28x%29=+-0.4x%5E2%2B20x%2B122.1\"
\n" ); document.write( "Just substitute for x with the number of days.
\n" ); document.write( "I'll do one you do the rest.
\n" ); document.write( "For \"x=10\",
\n" ); document.write( "\"T%2810%29=+-0.4%2810%29%5E2%2B20%2810%29%2B122.1\"
\n" ); document.write( "\"T%2810%29=+-0.4%28100%29%2B200%2B122.1\"
\n" ); document.write( "\"T%2810%29=+-40%2B222.1\"
\n" ); document.write( "\"T%2810%29=182.1\"
\n" ); document.write( "Since you can't sell 0.1 of a ticket, on the 10th day, 182 tickets were sold.
\n" ); document.write( "Follow the same process for \"x=20\", \"x=40\", and \"x=50\".\r
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