document.write( "Question 368261: e^2x - 4e^x + 3 = 0; upon recognizing that e^2x = (e^x)^2, and thus the above equation is a quadratic in terms of e^x. Solve the equation\r
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Algebra.Com's Answer #262410 by robertb(5830)\"\" \"About 
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\"%28e%5Ex-1%29%28e%5Ex-3%29+=+0\",
\n" ); document.write( "\"e%5Ex+=+1\", or \"e%5Ex+=+3\".
\n" ); document.write( "x = 0 or x = ln3.
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