document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37660>Question 37660</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0201812487/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26241 by </B><A HREF=/tutors/aboutme.mpl?userid=mszlmb><B>mszlmb(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mszlmb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mszlmb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter=length(2)+width(2)<BR>\n" );
document.write( "1/4L=2W  divide both sides by 2<BR>\n" );
document.write( "1/8L=W, meaning the W:L ratio is 1:.125<BR>\n" );
document.write( "sooo<BR>\n" );
document.write( "2(X+.125X)=150  X is the width and .125X is the length..divide by 2<BR>\n" );
document.write( "1.125X=75   becuz 1x+.125x=1.125x..divide by 1.125<BR>\n" );
document.write( "x=66 2/3\r<BR>\n" );
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document.write( "The dennmitois are X and 1.125X, namely, 66.6667, and 7.5\r<BR>\n" );
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document.write( "Pesale Cechk it oevr to fnid if I am rihgt or wnorg<BR>\n" );
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