document.write( "Question 368228: a chemist mixes a 20% acid solution with a 60%acid solution to make 40 gallons of a 50%acid solution and how much of the 20% soloion and how much of the 60% solution was used \n" ); document.write( "
Algebra.Com's Answer #262386 by mananth(16946)![]() ![]() You can put this solution on YOUR website! a chemist mixes a 20% acid solution with a 60%acid solution to make 40 gallons of a 50%acid solution and how much of the 20% soloion and how much of the 60% solution was used \n" ); document.write( ".. \n" ); document.write( " 20% acid solution : x gallons \n" ); document.write( " 60%acid solution : 40-x \n" ); document.write( " 50%acid solution 40 gallons \n" ); document.write( ".. \n" ); document.write( "0.2x+0.6(40-x)= 0.5*40 \n" ); document.write( "0.2x+24x-0.6x=20 \n" ); document.write( "-0.4x= -4 \n" ); document.write( "/-0.4 \n" ); document.write( "x= 10 gallons---- 20% \n" ); document.write( "... \n" ); document.write( "30 gallons 60% solution \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |