document.write( "Question 368228: a chemist mixes a 20% acid solution with a 60%acid solution to make 40 gallons of a 50%acid solution and how much of the 20% soloion and how much of the 60% solution was used \n" ); document.write( "
Algebra.Com's Answer #262386 by mananth(16946)\"\" \"About 
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a chemist mixes a 20% acid solution with a 60%acid solution to make 40 gallons of a 50%acid solution and how much of the 20% soloion and how much of the 60% solution was used
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\n" ); document.write( " 20% acid solution : x gallons
\n" ); document.write( " 60%acid solution : 40-x
\n" ); document.write( " 50%acid solution 40 gallons
\n" ); document.write( "..
\n" ); document.write( "0.2x+0.6(40-x)= 0.5*40
\n" ); document.write( "0.2x+24x-0.6x=20
\n" ); document.write( "-0.4x= -4
\n" ); document.write( "/-0.4
\n" ); document.write( "x= 10 gallons---- 20%
\n" ); document.write( "...
\n" ); document.write( "30 gallons 60% solution
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\n" ); document.write( "m.ananth@hotmail.ca
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