document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40618>Question 40618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My Question\r<BR>\n" );
document.write( "\n" );
document.write( "A piece of string 25 cm long goes exactly once around the edge of a plate in the form of a quadrant.  Calculate the area of the quadrant. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26233 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A quadrant (of a circle) has a perimeter of 2r + (1/2)(pi)r<BR>\n" );
document.write( "If that equals 25, we can solve for r and then plug that into the formula for the area of it...A = (1/4)(pi)r^2<BR>\n" );
document.write( "so we have<BR>\n" );
document.write( "2r + (1/2)(pi)r = 25<BR>\n" );
document.write( "r = 25 / (2 + (1/2)(pi))<BR>\n" );
document.write( "A = (1/4)(pi)r^2<BR>\n" );
document.write( "A = (1/4)(pi)(25 / (2 + (1/2)(pi)))^2<BR>\n" );
document.write( "you can work out the exact value if needed... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );