document.write( "Question 368114: A man passed one sixth of his life in childhood, one twelfth in youth, and one seven more as a bachelor. Five years after his marriage, a son was born who died four years before his father at half his father's final age. What was the man's final age? \n" ); document.write( "

Algebra.Com's Answer #262327 by robertb(5830) $\"\"$ $\"About$

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Let M= man's final age. Then
\n" ); document.write( " $\"M%2F6+%2BM%2F12+%2B+M%2F7+%2B+5%2BM%2F2+%2B+4+=+M\"$ . Multiply both sides by 84, the LCD.
\n" ); document.write( " $\"14M%2B7M+%2B+12M+%2B+420+%2B+42M%2B336+=+84M\"$ ,
\n" ); document.write( " $\"75M+%2B+756+=+84M\"$ ,
\n" ); document.write( " $\"756+=+9M\"$ ,
\n" ); document.write( "M = 84, the man's final age. \n" ); document.write( "

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