document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368058>Question 368058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> pop+of=opp </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262319 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> pop + of = opp.<BR>\n" );
document.write( "From the ones places, we get p + f = p, so we know f = 0.<BR>\n" );
document.write( "From the tens places, we get 2*o = 10+p, and carrying the one over to the hundreds place gives us 1 + p =o, so we have the system:<BR>\n" );
document.write( "2o = 10 + p<BR>\n" );
document.write( "1 + p = o.<BR>\n" );
document.write( "By direct substitution ofthe bottom equation into the top equation, we get<BR>\n" );
document.write( "2(1+p) = 10+p, or<BR>\n" );
document.write( "2 + 2p = 10 + p, or<BR>\n" );
document.write( "p = 8.  Then o = 9.  <BR>\n" );
document.write( "Thus we have<BR>\n" );
document.write( "898<BR>\n" );
document.write( "+90<BR>\n" );
document.write( "---<BR>\n" );
document.write( "988 </SPAN>\n" );
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