document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368033>Question 368033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two-thirds of a number is decreased by 3 is 2 more than half the number. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262278 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3X-3=X/2+2<BR>\n" );
document.write( "2X/3-3=X/2+2<BR>\n" );
document.write( "2X/3-X/2=2+3<BR>\n" );
document.write( "(2*2X-3X)/3*2=5<BR>\n" );
document.write( "(4X-3X)/6=5<BR>\n" );
document.write( "X/6=5<BR>\n" );
document.write( "X=5*6<BR>\n" );
document.write( "X=30 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(2/3)30-3=30/2+2<BR>\n" );
document.write( "60/3-3=15+2<BR>\n" );
document.write( "20-3=17<BR>\n" );
document.write( "17=17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );