document.write( "Question 368020: solve the equation:\r
\n" ); document.write( "\n" ); document.write( "log4 + 2logx =log (x+3)^2
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Algebra.Com's Answer #262274 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log4 + 2logx =log (x+3)^2
\n" ); document.write( "log4 + logx^2 =log (x+3)^2
\n" ); document.write( "log(4x^2) =log (x+3)^2
\n" ); document.write( "4x^2 =(x+3)^2
\n" ); document.write( "2x =x+3
\n" ); document.write( "x = 3
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