document.write( "Question 367893: find three consecutive odd integers such that three times the first is 9 greater than six times the third \n" ); document.write( "

Algebra.Com's Answer #262215 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the smallest of the three consecutive odd integers.
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document.write( "The next two consecutive odd integers would be (x+2) and (x+4)
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document.write( "Write as we Read***
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document.write( "3x = 6(x+4) + 9
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document.write( "solve for x
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document.write( "3x = 6x + 24 + 9
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document.write( "-33 = 3x
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document.write( "-11 =x
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document.write( "the three consecutive odd integers are -11, -9 and -7
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document.write( "checking our answer
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document.write( "3*-11 = -33 = 6*-7 + 9  \n" );
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