document.write( "Question 5163: Allison invested $2200 in two banks. At the first bank she had an interest rate of 4 1/2% and at the second bank the interest rate was 5 3/4%. If the interest obtained at teh end of the year was $107.75, how much was invested at 5 3/4%.\r
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document.write( "O.K. This one is killing me. The book's answer is $700.00\r
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document.write( "First I changed the into decimals. For 4 1/2 - 0.45 and 0.575\r
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document.write( "Then I tried to make a equations, by using the invested amount.
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document.write( "0.45x + (2000-X)0.575=107.75
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document.write( "0.45x + 1,150 - 0.575x = 107.75
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document.write( "0.125x = 1042.25\r
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document.write( "I am stumped. Am completely wrong? Please tell me what I am doing wrong.
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document.write( "Thank you
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Algebra.Com's Answer #2621 by guapa(62)![]() ![]() ![]() You can put this solution on YOUR website! You are not completely wrong. You copied a wrong value from the question. The amount invested is $2200. You use $2000. \n" ); document.write( "Furthermore, I would suggest that if you express % in decimals you divide by 100. \n" ); document.write( "0.0575(x)+0.045(2200-x)=107.75 \n" ); document.write( "0.0575x + 99- 0.045x=107.75 \n" ); document.write( "0.0125x = 8,75 \n" ); document.write( "x = 700 \n" ); document.write( " |