document.write( "Question 367629: the perimeter fence of a rectangle community is 310m. Its length is 10 meter less than twice its width. Find the dimensions of the park. \n" ); document.write( "
Algebra.Com's Answer #262041 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Let x represent the width, then (2x-10m) would be the length
\n" ); document.write( "2*(2x - 10m) + 2*x = 310m (the perimeter)
\n" ); document.write( "solving for x
\n" ); document.write( "4x - 20m + 2x = 310m
\n" ); document.write( "6x = 330m
\n" ); document.write( "x = 55m, the width. the length is 100m (2*55m - 10)\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "110 + 200 = 310 \n" ); document.write( "
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