document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367583>Question 367583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is 40 and its base is 32. Find the base of a similar triangle whose area is 90. .  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261998 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let k = constant of proportionality between the two similar triangles(bigger-to-smaller.)Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%2F40+=+k%5E2 ALIGN=MIDDLE  ALT=\"90%2F40+=+k%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. or k = 3/2.  Thus the base of the bigger triangle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2F2%29%2A32+=+48 ALIGN=MIDDLE  ALT=\"%283%2F2%29%2A32+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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