document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367541>Question 367541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the product of 3and a number is increased by 7,the result is 23 greater than the number find the number. \r<BR>\n" );
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document.write( "ok,so i know how to do the problem i just do not know how to write it out. <BR>\n" );
document.write( "at first i thought it was (3x)+7=23>x but then i thought about it and was thinking it was 3(x+7)=23>x  \r<BR>\n" );
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document.write( "I DONT KNOW! Please help me quickly...Please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261980 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+7=x+23<BR>\n" );
document.write( "2x=16<BR>\n" );
document.write( "x=8 </SPAN>\n" );
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