document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367496>Question 367496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following systems of equations by using the addition method?<BR>\n" );
document.write( "2x-y=3<BR>\n" );
document.write( "x-2y=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261977 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the top equation by -2: -4x+2y = -6.<BR>\n" );
document.write( "Then add to the bottom equation: -4x+2y + x-2y = -6+9, or -3x = 3, or x = -1.<BR>\n" );
document.write( "This makes the bottom equation -1-2y = 9, or -2y = 10, or y = -5. </SPAN>\n" );
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