document.write( "Question 367531: sqrt(x+3)+1=sqrt(3x-2) Solve for x \n" ); document.write( "
Algebra.Com's Answer #261966 by mananth(16946)![]() ![]() You can put this solution on YOUR website! sqrt(x+3)+1=sqrt(3x-2) Solve for x \n" ); document.write( "... \n" ); document.write( "square both sides \n" ); document.write( ".. \n" ); document.write( "(sqrt(x+3)+1)^2=(sqrt(3x-2))^2 \n" ); document.write( "(x+3)+2sqrt(x+3)+1 = 3x-2 \n" ); document.write( "x+3 -3x+2+1= -2sqrt(x+3) \n" ); document.write( "-2x+6=-2sqrt(x+3) \n" ); document.write( "-2(x-3)=-2(sqrt(x+3) \n" ); document.write( "divide by -2 \n" ); document.write( "(x-3)^2= sqrt(x+3) \n" ); document.write( "square \n" ); document.write( "x^2-6x+9 = x+3 \n" ); document.write( "x^2-6x-x+9-3=0 \n" ); document.write( "x^2-7x+6=0 \n" ); document.write( "x^2-6x-x+6=0 \n" ); document.write( "x(x-6)-1(x-6)=0 \n" ); document.write( "(x-6)(x-1)=0 \n" ); document.write( "x 6 Or 1 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |