document.write( "Question 367531: sqrt(x+3)+1=sqrt(3x-2) Solve for x \n" ); document.write( "
Algebra.Com's Answer #261966 by mananth(16946)\"\" \"About 
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sqrt(x+3)+1=sqrt(3x-2) Solve for x
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\n" ); document.write( "square both sides
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\n" ); document.write( "(sqrt(x+3)+1)^2=(sqrt(3x-2))^2
\n" ); document.write( "(x+3)+2sqrt(x+3)+1 = 3x-2
\n" ); document.write( "x+3 -3x+2+1= -2sqrt(x+3)
\n" ); document.write( "-2x+6=-2sqrt(x+3)
\n" ); document.write( "-2(x-3)=-2(sqrt(x+3)
\n" ); document.write( "divide by -2
\n" ); document.write( "(x-3)^2= sqrt(x+3)
\n" ); document.write( "square
\n" ); document.write( "x^2-6x+9 = x+3
\n" ); document.write( "x^2-6x-x+9-3=0
\n" ); document.write( "x^2-7x+6=0
\n" ); document.write( "x^2-6x-x+6=0
\n" ); document.write( "x(x-6)-1(x-6)=0
\n" ); document.write( "(x-6)(x-1)=0
\n" ); document.write( "x 6 Or 1
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\n" ); document.write( "m.ananth@hotmail.ca
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