document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367386>Question 367386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An Archer shoots an arrow. It's heights (in inches) at three times (in seconds) are given:\r<BR>\n" );
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document.write( "Time is t<BR>\n" );
document.write( "Distance above ground is s\r<BR>\n" );
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document.write( "at 3 seconds, the arrow was 326 ft above the ground<BR>\n" );
document.write( "at 5 seconds, the arrow was 350 ft above the ground<BR>\n" );
document.write( "at 8 seconds, the arrow was 146 ft above the ground\r<BR>\n" );
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document.write( "What is the maximum height of the arrow?\r<BR>\n" );
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document.write( "So far, all I have is s=-16t^2+140t+50, but I have no idea how to get the height of the arrow from there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261951 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the maximum value is the vertex of the parabola , which lies on the axis of symmetry\r<BR>\n" );
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document.write( "the general equation is ___ x = -b / (2a)\r<BR>\n" );
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document.write( "find x and then plug into your equation to find s </SPAN>\n" );
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