document.write( "Question 367415: Hi, I have to write \"f%28x%29+=+x%5E4\"\"625\" as a product of linear factors.\r
\n" ); document.write( "\n" ); document.write( "Since \"25%5E2+=+625\", I determined that \"f%28x%29+=+%28x%5E2+%2B+25%29%28x%5E2+-+25%29\"\r
\n" ); document.write( "\n" ); document.write( "Then I was able to factor some more below, but I believe I should be taking the square root of the equation at some point, just not sure where.\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+%2B+25%29%28x+%2B+5%29%28x+-+5%29\"\r
\n" ); document.write( "\n" ); document.write( "Thanks for any help you can provide!
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Algebra.Com's Answer #261944 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Yes, what you have is correct,
\n" ); document.write( "\"x%5E4-625=%28x%5E2%2B25%29%28x-5%29%28x%2B5%29\"
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\n" ); document.write( "No need to take a square root.
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