document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367423>Question 367423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There were 590 people at play. the admission price was $3.00 for adults and $1.00 for children. The admission receipts were $1070. How many adults and children attended. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261909 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hey, <BR>\n" );
document.write( "For this one we need to split this problem into two equations:\r<BR>\n" );
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document.write( "a (adults) + c (children) = 590<BR>\n" );
document.write( "3a + c = 1070<BR>\n" );
document.write( "Then we substitute 590 - a for c in the second equation.<BR>\n" );
document.write( "3a + 590 - a = 1070<BR>\n" );
document.write( "2a + 590 = 1070<BR>\n" );
document.write( "2a = 560<BR>\n" );
document.write( "a = 280<BR>\n" );
document.write( "Then we plug this into the first equation:<BR>\n" );
document.write( "280 + c = 590<BR>\n" );
document.write( "c = 310<BR>\n" );
document.write( "I hope this helps! </SPAN>\n" );
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