document.write( "Question 367307: Solve
\n" ); document.write( " $\"+x%2B3sqrt%28x%29-40=0+\"$ \n" ); document.write( "

Algebra.Com's Answer #261898 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+x%2B3sqrt%28x%29-40=0+\"$ ,
\n" ); document.write( " $\"%28sqrt%28x%29-5%29%28sqrt%28x%29%2B8%29+=+0\"$ .
\n" ); document.write( "Hence $\"sqrt%28x%29+=+5\"$ , or $\"sqrt%28x%29+=+-8\"$ .
\n" ); document.write( "The second equation has no solution (extraneous solution!), while the first gives x = 25. This also satisfies the original equation, so this is the final answer. \n" ); document.write( "

\n" );