document.write( "Question 367266: Find the lengths of the sides of the triangles: sides are x and x+1 and the hypotenuse is x+4. So I end up getting x^2 -6x-15= 0 but I don't know how to factor this. What am I doing wrong? \n" ); document.write( "
Algebra.Com's Answer #261895 by Alan3354(69443)\"\" \"About 
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Find the lengths of the sides of the triangles: sides are x and x+1 and the hypotenuse is x+4. So I end up getting x^2 -6x-15= 0 but I don't know how to factor this. What am I doing wrong?
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\n" ); document.write( "\"x%5E2+%2B+%28x%2B1%29%5E2+=+%28x%2B4%29%5E2\"
\n" ); document.write( "\"2x%5E2+%2B+2x+%2B+1+=+x%5E2+%2B+8x+%2B+16\"
\n" ); document.write( "\"x%5E2+-+6x+-+15+=+0\"
\n" ); document.write( "It doesn't factor
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-6x%2B-15+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-6%29%5E2-4%2A1%2A-15=96\".
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\n" ); document.write( " Discriminant d=96 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--6%2B-sqrt%28+96+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-6%29%2Bsqrt%28+96+%29%29%2F2%5C1+=+7.89897948556636\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-6%29-sqrt%28+96+%29%29%2F2%5C1+=+-1.89897948556636\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-6x%2B-15\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-6x%2B-15+=+%28x-7.89897948556636%29%2A%28x--1.89897948556636%29\"
\n" ); document.write( " Again, the answer is: 7.89897948556636, -1.89897948556636.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-6%2Ax%2B-15+%29\"

\n" ); document.write( "\n" ); document.write( "Ignore the negative number
\n" ); document.write( "x = 3 + 2sqrt(6)
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