document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40795>Question 40795</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0536965943/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A semi-truck travels 300 miles through the flatland in the same amount of time that it travels 180 miles through mountains.  The rate of the truck is 20 miles per hour slower in the mountains than in the flatland.  Find both the flatland rate and the mountain rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26184 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r = the trucks rate in the mountains<BR>\n" );
document.write( "r + 20 will be the rate on flat land<BR>\n" );
document.write( "The semi-truck travels 300 miles through the flatland in the same amount of time that it travels 180 miles through mountains.<BR>\n" );
document.write( "Let t = the time for both trips<BR>\n" );
document.write( "t = 180/r<BR>\n" );
document.write( "t = 300/(r + 20)<BR>\n" );
document.write( "180/r = 300/(r + 20)<BR>\n" );
document.write( "multiply both sides by r(r+20)<BR>\n" );
document.write( "180(r+20) = 300r<BR>\n" );
document.write( "180r + 3600 = 300r<BR>\n" );
document.write( "subtract 180r from both sides<BR>\n" );
document.write( "3600 = 120r<BR>\n" );
document.write( "r = 30 the rate in the mountains<BR>\n" );
document.write( "r + 20 = 50 the rate on flat land<BR>\n" );
document.write( "check<BR>\n" );
document.write( "180/r = 300/(r + 20)<BR>\n" );
document.write( "180/30 = 300/50<BR>\n" );
document.write( "6 = 6<BR>\n" );
document.write( "OK  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );