document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367317>Question 367317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train b is traveling at 110 miles per hour. Train A passes a station at 10:15am. If train B passes the same station at 10:45 am. at what time will train B catch up with train A.<BR>\n" );
document.write( "When will Train B catch up with train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261839 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train b is traveling at 110 miles per hour. Train A passes a station at 10:15am. If train B passes the same station at 10:45 am. at what time will train B catch up with train A.<BR>\n" );
document.write( "When will Train B catch up with train A?<BR>\n" );
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document.write( "In 0.5 hours train A goes 50 miles (100*0.5)<BR>\n" );
document.write( "Train B gains on train A at 10 mph (110 - 100)<BR>\n" );
document.write( "50/10 = 5 hours<BR>\n" );
document.write( "10:45 + 5 = 1545, or 3:45 PM<BR>\n" );
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