document.write( "Question 367297: Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5) \n" ); document.write( "
Algebra.Com's Answer #261818 by nerdybill(7384) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5) \n" ); document.write( ".56 \n" ); document.write( "Because \n" ); document.write( "y = 1/3 x + 7 \n" ); document.write( "is in \"slope-intercept\" form: y=mx+b \n" ); document.write( "We can see that the slope is: 1/3 \n" ); document.write( ". \n" ); document.write( "For a line to be perpendicular, the slope of the new line must be the \"negative reciprocal\": \n" ); document.write( "(1/3)m = -1 \n" ); document.write( "m = -3 (slope of our new line) \n" ); document.write( ". \n" ); document.write( "Given that the problem stated that the y-intercept is at (0,5) this means that the 'b' (in the slope intercept form) is 5 \n" ); document.write( ". \n" ); document.write( "So, our equation is: \n" ); document.write( "y = -3x + 5 (this is what they're looking for)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |