document.write( "Question 367297: Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5) \n" ); document.write( "
Algebra.Com's Answer #261818 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5)
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\n" ); document.write( "Because
\n" ); document.write( "y = 1/3 x + 7
\n" ); document.write( "is in \"slope-intercept\" form: y=mx+b
\n" ); document.write( "We can see that the slope is: 1/3
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\n" ); document.write( "For a line to be perpendicular, the slope of the new line must be the \"negative reciprocal\":
\n" ); document.write( "(1/3)m = -1
\n" ); document.write( "m = -3 (slope of our new line)
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\n" ); document.write( "Given that the problem stated that the y-intercept is at (0,5) this means that the 'b' (in the slope intercept form) is 5
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\n" ); document.write( "So, our equation is:
\n" ); document.write( "y = -3x + 5 (this is what they're looking for)\r
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