document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367247>Question 367247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One third of a number decreased by 2 is the same as that number increased by 6. Find that number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261793 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One third of a number decreased by 2 is the same as that number increased by 6. Find that number.\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(1/3)x -2 = x+6<BR>\n" );
document.write( "(1/3)x = x+8<BR>\n" );
document.write( "Subtract (1/3)x from both sides.<BR>\n" );
document.write( "Subtract 8 from both sides.<BR>\n" );
document.write( "(2/3)x = -8<BR>\n" );
document.write( "(1/3)x = -4<BR>\n" );
document.write( "x = -12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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