document.write( "Question 367156: Where do I start?
\n" ); document.write( "OLD COINS: A salesperson used her $3,500 year-end bonus to purchase some old coins, with hopes of earning 15% annual interest on the gold coins and 12% annual interest on the silver coins. If she saw return on her investment of $480 the first year, how much did she invest in each type of coin?
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Algebra.Com's Answer #261772 by Earlsdon(6294)\"\" \"About 
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You can start by assigning variables to the unknown quantities, the invested amounts in gold and in silver.
\n" ); document.write( "Let G = the number of dollars invested in gold and S = the number of dollars invested in silver.
\n" ); document.write( "The sum of these two amounts is given as $3,500.00, so you can write:
\n" ); document.write( "1) \"G%2BS+=+3500\"
\n" ); document.write( "Now we must find an equation for the amount of interest earned.
\n" ); document.write( "The interest earned on the gold investment is 15%(G) and the interest earned on the silver investment is 12%(S), and the sum of these two amounts is given as $480.00
\n" ); document.write( "So, after changing the percents to their decimal equivalents, you can write the equation:
\n" ); document.write( "2) \"0.15G%2B0.12S+=+480\"
\n" ); document.write( "Now let's replace the G in equation 2) with its equivalent: \"G+=+3500-S\" which we get from equation 1) by solving for G.
\n" ); document.write( "3) \"0.15%283500-S%29%2B0.12S+=+480\" Simplify and solve for S.
\n" ); document.write( "3a) \"525-0.15S%2B0.12S+=+480\"
\n" ); document.write( "3b) \"525-0.03S+=+480\" Subtract 525 from both sides.
\n" ); document.write( "3c) \"-0.03S+=+-+45\" Finally, divide both sides by -0.03
\n" ); document.write( "3d) \"highlight%28S+=+1500%29\" This is the number of dollars invested in silver.
\n" ); document.write( "\"G+=+3500-S\"
\n" ); document.write( "\"G+=+3500-1500\"
\n" ); document.write( "\"highlight_green%28G+=+2000%29\" and this is the number of dollars invested in gold.
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