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A cylindrical hot water tank has an outside diameter of 0.4 yards and a height of 1.2 yards. It's outside is to be completely covered with an insulating material which is 1.2 inches thick. Calculate the volume of the insulating material required.
\n" ); document.write( "I found lateral surface area of 1.507964474. area of bottom of 0.125663706 for a total area of 1.63362818. Do I need to compensate for the top too? Where do I go next to get the volume of material?
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\n" ); document.write( "The diameter of the top and the bottom of the tank is (0.4*36) = 14.4 inches
\n" ); document.write( "The area of top of the tank is (pi)7.2^2 = 162.86in^2
\n" ); document.write( "The height of the tank is (1.2*36) = 43.2 in
\n" ); document.write( "The Volume of the tank is (162.86*43.2) = 7035.55 in^3
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\n" ); document.write( "The diameter of the top and bottom insulation is (14.4+2*1.2) = 16.8 inches
\n" ); document.write( "The area of the top and of the bottom is (pi)8.4^2 = 221.67 in^2
\n" ); document.write( "The height of the tank with the insulation cover is (43.2+2*1.2) = 45.6 inches
\n" ); document.write( "The Volume of the covered tank cylinder is (221.67*45.6) = 10108.15 in^3
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\n" ); document.write( "The Vol of the insulation is 10108.15-7035.55 = 3072.59 in^3 = 1.7781 yrd^3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "