document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367048>Question 367048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center-radius form of the circle whose equation is<BR>\n" );
document.write( "x2 + 6x + y^2 - 2y + 6 = 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261689 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x2 + 6x + y^2 - 2y + 6 = 0.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(x^2+6x+9)-9 +(y^2-2y+1)-1 +6=0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(x+3)^2 +(y-1)^2 -9-1+6=0<BR>\n" );
document.write( "(x+3)^2 +(y-1)^2 = 4<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Center (-3,1)<BR>\n" );
document.write( "radius = sqrt4 =2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );