document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367024>Question 367024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to help my grandson with his algebra. The equation is<BR>\n" );
document.write( "7(6-2a)=5(-3a+1).  <BR>\n" );
document.write( "this is my work but I know it is wrong. Please help me.<BR>\n" );
document.write( "7(6-2a+2a) + 5(-3a+1+2a)<BR>\n" );
document.write( "7(6)=5(-a+1<BR>\n" );
document.write( "7(6-1)=5(-a)<BR>\n" );
document.write( "35=-5a<BR>\n" );
document.write( "a = -7<BR>\n" );
document.write( "where did I go wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261671 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply through first<BR>\n" );
document.write( "7(6-2a)=5(-3a+1)<BR>\n" );
document.write( "42-14a=-15a+5<BR>\n" );
document.write( "add 15a to both sides<BR>\n" );
document.write( "and subtract 42 from both sides<BR>\n" );
document.write( "a=-37<BR>\n" );
document.write( "Does that help?<BR>\n" );
document.write( "Bob </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );