document.write( "Question 367018: I've been working on this problem for 5 days and can't figure it out. This is the question. \"A homeowner has poured a rectangular slab for a barbecue pit. The length is 3 feet more than its width. It is surrounded by a 2 foot wide flower bed. If the area covered by both is 270 square feet, find the dimensions of the barbecue area\".\r
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document.write( "1. A=lw which would mean that the with is 15 and the length is 18 (18*15=270). Now if you subtract the perimeter of that, which would be 8 feet (2*4=8) that would mean that the remaining area would be 262.
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document.write( "2. At 51 I suck at word problems as bad as I did when I was 15 and just can not figure out how to put this in a quadratic equation. I have tried 270=(w+3)(w)-2^2 and it doesn't work.
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document.write( "I have tried x=(w+3)(w)-2^2-270 and that doesn't work.\r
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document.write( "What exactly is it that I'm doing wrong?\r
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document.write( "3. Yes, this is a homework problem and yes I have tried everything to solve it. I have read and re-read the chapter and my class notes but it just comes down to I don't understand...Please Help!!!1\r
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document.write( "Susan Lucas \n" );
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Algebra.Com's Answer #261667 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The outer edges of the pit and flower bed are then, \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Two solutions but only the positive one makes sense. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The barbeque pit is 13 ft by 16 ft. \n" ); document.write( " |