document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=367013>Question 367013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The formula r=2sqrt5L can be used to approximate the speed r, in miles per hour, of a car that has left skid marks of length L, in feet.  How far will a car skid at 70 mph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261655 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=2sqrt5L can be used to approximate the speed r, in miles per hour, of a car that has left skid marks of length L, in feet.  How far will a car skid at 70 mph?<BR>\n" );
document.write( "...<BR>\n" );
document.write( "70 = 2sqrt5L<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "35=sqrt5L<BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "35^2= 5L<BR>\n" );
document.write( "35^2/5 = L<BR>\n" );
document.write( "L = 245 feet<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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