document.write( "Question 366837: How do you solve for this inequality algebraically.
\n" ); document.write( "(x+1)(x-2)(2^x) > 0 \n" ); document.write( "

Algebra.Com's Answer #261629 by robertb(5830) $\"\"$ $\"About$

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$\"%28x%2B1%29%28x-2%29%282%5Ex%29+%3E+0+\"$ .
\n" ); document.write( "The factor $\"2%5Ex+%3E0\"$ for all real values of x, and so we can just eliminate it from the inequality by dividing both sides by it. Hence we're actually solving
\n" ); document.write( " $\"%28x%2B1%29%28x-2%29%3E+0+\"$ . The critical numbers are -1 and 2. Choosing test numbers x = -2, 0 and 3, we find out that the solution set is ( $\"-infinity\"$ , -1)U(2, $\"infinity\"$ ). \n" ); document.write( "

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