document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366975>Question 366975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store buys granola at $1/lb and dried fruit at $2/lb. and sells them at 25% markup. The store sells 2 special mixtures of granola and dried fruit.  One customer buys 6 lbs. of Mixture A and 4 lbs of Mixture B and pays $17.  Another custoemr reverses the proportions and pays a dollar more.   \r<BR>\n" );
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document.write( "What is the recipe for Mixture A?<BR>\n" );
document.write( "What is the recipe for Mixture B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261604 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A store buys granola at $1/lb and dried fruit at $2/lb. and sells them at 25% markup. The store sells 2 special mixtures of granola and dried fruit.  One customer buys 6 lbs. of Mixture A and 4 lbs of Mixture B and pays $17.  Another custoemr reverses the proportions and pays a dollar more.   \r<BR>\n" );
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document.write( "Given:<BR>\n" );
document.write( "Selling Prices<BR>\n" );
document.write( "Granola     : $1 plus 25% mark-up = $1.25/lb<BR>\n" );
document.write( "Dried Fruit : $2 plus 25% mark-up = $2.50/lb\r<BR>\n" );
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document.write( "Let A = Selling price of mixture A<BR>\n" );
document.write( "    B = Selling price of mixture B\r<BR>\n" );
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document.write( "Equation 1<BR>\n" );
document.write( "6A + 4B = 17\r<BR>\n" );
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document.write( "Equation 2<BR>\n" );
document.write( "4A + 6B = 18<BR>\n" );
document.write( "multiply equation 2 by 1.5 <BR>\n" );
document.write( "6A + 9B = 27<BR>\n" );
document.write( "deduct equation 2 by equation 1\r<BR>\n" );
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document.write( "(6A-6A)+ (9B-4B) = 27 -17<BR>\n" );
document.write( "             5B  = 10<BR>\n" );
document.write( "              B  = 2\r<BR>\n" );
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document.write( "substitute B=2 in equation1<BR>\n" );
document.write( "6A + 4(2) = 17<BR>\n" );
document.write( "      6A  = 17-8<BR>\n" );
document.write( "       A  = 1.5\r<BR>\n" );
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document.write( "If mixtures A & B is sold at Granola = $1 plus 25% mark-up = $1.25/lb<BR>\n" );
document.write( "& $2.00/lb respectively, we ca now compute the recipe for mixtures A & B\r<BR>\n" );
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document.write( "Given<BR>\n" );
document.write( "Selling prices<BR>\n" );
document.write( "Mixture A = $1.50/lb<BR>\n" );
document.write( "Mixture B = $2.00/lb\r<BR>\n" );
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document.write( "Let x = % of Granola in mixture A<BR>\n" );
document.write( "1.25x + 2.5(1-x) = 1.5<BR>\n" );
document.write( "              x  = 80%<BR>\n" );
document.write( "So recipe for mixture A is 80% Granola & 20% Dried Fruit\r<BR>\n" );
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document.write( "Let y = % 0f Granola in mixture B<BR>\n" );
document.write( "1.25 y + 2.5(1-y) = 2<BR>\n" );
document.write( "               y  = 40%<BR>\n" );
document.write( "So recipe for mixture B is 40% Granola & 60% Dried Fruit\r<BR>\n" );
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document.write( " </SPAN>\n" );
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