document.write( "Question 366975: A store buys granola at $1/lb and dried fruit at $2/lb. and sells them at 25% markup. The store sells 2 special mixtures of granola and dried fruit. One customer buys 6 lbs. of Mixture A and 4 lbs of Mixture B and pays $17. Another custoemr reverses the proportions and pays a dollar more. \r
\n" ); document.write( "\n" ); document.write( "What is the recipe for Mixture A?
\n" ); document.write( "What is the recipe for Mixture B?
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Algebra.Com's Answer #261603 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
6 lbs. of Mixture A number of pounds be x
\n" ); document.write( "4 lbs of Mixture B number of pounds be y
\n" ); document.write( "and pays $17.
\n" ); document.write( "6x+4y=17.....................................1\r
\n" ); document.write( "\n" ); document.write( "Another customer reverses the proportions
\n" ); document.write( "and pays a dollar more.
\n" ); document.write( "6y+4x=18.....................................2
\n" ); document.write( "...
\n" ); document.write( "multiply 1 by -4 & 2 by 6
\n" ); document.write( "-24x-16y=-68
\n" ); document.write( "36y+24x=108
\n" ); document.write( "..
\n" ); document.write( "add up
\n" ); document.write( "20y=40
\n" ); document.write( "/20
\n" ); document.write( "y = 2 price of Mixture B
\n" ); document.write( "plug value of y in
\n" ); document.write( "6x+4y=17
\n" ); document.write( "6x+8=17
\n" ); document.write( "6x=9
\n" ); document.write( "/6
\n" ); document.write( "x= 3/2 the price of mixture A
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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