document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366952>Question 366952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters will have to be drained and then replaced with pure anitfreeze if the resulting solution is to be 50 percent antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261587 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters will have to be drained and then replaced with pure anitfreeze if the resulting solution is to be 50 percent antifreeze?<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "anti - anti + anti = anti<BR>\n" );
document.write( "0.20*10 - 0.20x + 1.00x = 0.50*10<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "20*10 - 20x + 100x = 50*10<BR>\n" );
document.write( "80x = 30*10<BR>\n" );
document.write( "x = 3.75 liters (amt. that must be removed and replaced)<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );