document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366896>Question 366896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x-3=8x-9 , x=? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261544 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x - 3 = 8x - 9  |subs 6x on both side <BR>\n" );
document.write( " <BR>\n" );
document.write( "6x - 3 - 6x = 8x - 9 - 6x<BR>\n" );
document.write( " <BR>\n" );
document.write( "-3 = 2x - 9 | +9 on both side<BR>\n" );
document.write( " <BR>\n" );
document.write( "6 = 2x, two times x is six, hence x = 3<BR>\n" );
document.write( " <BR>\n" );
document.write( " <BR>\n" );
document.write( "Verification : <BR>\n" );
document.write( " <BR>\n" );
document.write( " 6*3 - 3 = 18 - 3 = 15 (LHS)<BR>\n" );
document.write( " <BR>\n" );
document.write( " 8*3 - 9 = 24 - 9 = 15 (RHS) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );