document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40587>Question 40587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A worm is at the bottom of a 12 ft. wall.  Every day it crawls up 3 ft., but at night it slips down 2 ft.  How many days does it take the worm to get to the top of the wall? How do I solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26154 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Height for climbing 12<BR>\n" );
document.write( "Daily climbing rate = 3<BR>\n" );
document.write( "daily sipping rate  = 2<BR>\n" );
document.write( "Net height climbed per day = 1 <BR>\n" );
document.write( "Like this, on day 9 it will on the 9 foot marking<BR>\n" );
document.write( "on day 10 it will reach the top ( 9 + 3) = 12<BR>\n" );
document.write( "At the top it need not slip !!<BR>\n" );
document.write( "Bravo.. </SPAN>\n" );
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