document.write( "Question 366881: A carpenter charges a set fee for each job in addition to his hourly charge. If he bills a cutomer $125 for ajob which takes him 3 hours and bills a second customer $200 for a 6 hour job, how much would he charge for a job that takes him 8 hours? \n" ); document.write( "
Algebra.Com's Answer #261532 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=set fee and y=hourly charge \n" ); document.write( "x+3y=125----eq1 \n" ); document.write( "and \n" ); document.write( "x+6y=200----eq2 \n" ); document.write( "subtract eq1 from eq2: \n" ); document.write( "3y=75 \n" ); document.write( "y=$25 per hour----hourly charge \n" ); document.write( "substitute y=$25 into eq1: \n" ); document.write( "x+75=125 or \n" ); document.write( "x=$50 set fee\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "50+75=125 \n" ); document.write( "and \n" ); document.write( "50+6*25=200 \n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |