document.write( "Question 366876: ½(y-2)+2 =3/8(3y-4) \r
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\n" ); document.write( "\n" ); document.write( "I am so confused with this problem. can you show me how to solve it step by step.\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "Michelle
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Algebra.Com's Answer #261519 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "***Note: let's proceed to have all denominators = 1
\n" ); document.write( "½(y-2)+ 2 =3/8(3y-4)
\n" ); document.write( "multiplying each term on both sides of the equation by 8 so as all denominators = 1
\n" ); document.write( "4(y-2) + 2*8 = 3(3y-4)
\n" ); document.write( "4y - 8 + 16 = 9y - 12
\n" ); document.write( "-8 + 16 + 12 = 5y
\n" ); document.write( "20 = 5y
\n" ); document.write( "4 = y\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "½(4-2)+ 2 =3/8(3*4-4) = 3 \n" ); document.write( "
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