document.write( "Question 40643: 54. A bicyclist rode into the county for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4h. What was her speed each way. \n" ); document.write( "
Algebra.Com's Answer #26150 by rajagopalan(174)\"\" \"About 
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Let onward speed = x
\n" ); document.write( "Let distance = d
\n" ); document.write( "on ward time = d/x = 5 (given) ..equation 1
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\n" ); document.write( "return\r
\n" ); document.write( "\n" ); document.write( "speed = x+5
\n" ); document.write( "distance = d
\n" ); document.write( "return journey time = d/(x+5)= 4 (given)..equation 2
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\n" ); document.write( "\n" ); document.write( "from eq 1 .. we get d/x=5, 5x=d\r
\n" ); document.write( "\n" ); document.write( "substitute d=5x in eqn 2\r
\n" ); document.write( "\n" ); document.write( "d/(x+5) = 4
\n" ); document.write( "5x/(x+5)=4
\n" ); document.write( "5x = 4(x+5)
\n" ); document.write( "5x = 4x+20
\n" ); document.write( "5x-4x = 20
\n" ); document.write( "x = 20.
\n" ); document.write( "Onward speed = 20
\n" ); document.write( "Return speed = 25 ..
\n" ); document.write( "good luck..\r
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