document.write( "Question 366657: a paddle wheeler goes 10 miles against the current in a river in the same time that it goes 15 miles with the current. If the speed of the current is 3 mph, find the speed of the boat in the water. \n" ); document.write( "
Algebra.Com's Answer #261344 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let speed of boat be x mph \n" ); document.write( "speed of current = 3mph\r \n" ); document.write( "\n" ); document.write( "..speed upstream \n" ); document.write( "x-3 mph \n" ); document.write( "distance =10 \n" ); document.write( "time upstream = 10/(x-3) \n" ); document.write( ".. \n" ); document.write( "downstream \n" ); document.write( "speed = x+3 \n" ); document.write( "distance = 15 miles \n" ); document.write( "time = 15/(x+y) \n" ); document.write( ".. \n" ); document.write( "times are same \n" ); document.write( "10/(x-3)=15/(x+3) \n" ); document.write( "10(x+3)=15(x-3) \n" ); document.write( "10x+30=15x-45 \n" ); document.write( "15x-10x=45-30 \n" ); document.write( "5x=15 \n" ); document.write( "x= 3 mph.... speed of boat \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |