document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366585>Question 366585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> system of four linear algebraic equation (get values of A,B, C and D)\r<BR>\n" );
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document.write( "0= Acos(t)+Bsin(t)+Ctcos(t)+Dtsin(t)+3t-2<BR>\n" );
document.write( "0=-Asin(t)+Bcos(t)+Ccos(t)-Ctsin(t)+Dsin(t)+Dtcos(t)+3<BR>\n" );
document.write( "1=-Acos(t)-Bsin(t)-2Csin(t)-Ctcos(t)+2Dcos(t)-Dtsin(t)<BR>\n" );
document.write( "1= Asin(t)-Bcos(t)-2Ccos(t)-Ccos(t)+Ctsin(t)-2Dsin(t)-Dsin(t)-Dtcos(t) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261324 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t = 0.  Then the system becomes<BR>\n" );
document.write( "0 = A-2,<BR>\n" );
document.write( "0 = B+C+3,<BR>\n" );
document.write( "1 = -A+2D,<BR>\n" );
document.write( "1 = -B-2C-C, or 1 = -B - 3C.<BR>\n" );
document.write( "The 1st equation gives A = 2.<BR>\n" );
document.write( "Substitution into the 3rd equation gives 1 = -2 + 2D, or D = 3/2.<BR>\n" );
document.write( "eliminating B from the 2nd and 4th equations gives C = 1.\r<BR>\n" );
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document.write( " Finally, substitution into the 2nd equation gives B=-4. </SPAN>\n" );
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