document.write( "Question 366527: find fourier series of cos^3 of x, and sin^3 of x ..
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Algebra.Com's Answer #261277 by Jk22(389)\"\" \"About 
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Given a function f(x) , we shall write the Fourier series of this.
\n" ); document.write( "There are series in complex exponential, sine or cosine. Let f(x) a function which is 2Pi periodic
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\n" ); document.write( "\"+f%28x%29=sum%28+a%5Bn%5D+cos%28nx%29%2C+n=0%2C+%2Binfinity+%29+\" is the series in cosine,
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\n" ); document.write( "with \"+a%5Bn%5D+=+%281%2Fpi%29+int%28+f%28x%29cos%28nx%29%2C+dx%2C+0%2C+2%2Api+%29\"
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\n" ); document.write( "since cos(mx) and cos(nx) are orthogonal functions.
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\n" ); document.write( "Consider an even function like cos(x)^3, only cosine (even) terms will appear.
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\n" ); document.write( "However without doing the integration, we can write cos(x) with complex numbers : cos(x) = (exp(ix)+exp(-ix))/2
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\n" ); document.write( "then cos(x)^3 = 1/8*(exp(i3x)+3exp(ix)+3exp(-ix)+exp(-i3x))
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\n" ); document.write( "= cos(3x)/4 + 3/4*cos(x)
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\n" ); document.write( " We can now show that this corresponds to the definition above :\r
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\n" ); document.write( "\n" ); document.write( "hence \"+8%2Aa%5B1%5D+=+6%2Api%2Fpi+-%3E+a%5B1%5D+=+3%2F4+\"
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\n" ); document.write( "The same can be shown for :
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\n" ); document.write( "the similar calculation can be done with sin(x) = (exp(ix) - exp(-ix))/(2i)
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\n" ); document.write( "sin(x)^3 = (exp(3ix) - 3exp(ix) + 3exp(-ix) - exp(-i3x))/(2i)^3
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\n" ); document.write( "= (- sin(3x) + 3sin(x))/4
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