document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366573>Question 366573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> YOU INVEST 4000 DOLLARS AT 6% COMPOUNDED MONTHLY, WHEN WILL YOU HAVE 25000 DOLLARS?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261236 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOU INVEST 4000 DOLLARS AT 6% COMPOUNDED MONTHLY, WHEN WILL YOU HAVE 25000 DOLLARS?\r<BR>\n" );
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document.write( "Let x = no. of months \r<BR>\n" );
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document.write( "A = pr^t\r<BR>\n" );
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document.write( "           25,000 = 4000(1+.06/12)^x<BR>\n" );
document.write( "           6.25   = (1.005)^x<BR>\n" );
document.write( "        (1.005)^x = 6.25<BR>\n" );
document.write( "    Log[(1.005)^x = 6.25]<BR>\n" );
document.write( "      x Log 1.005 = Log 6.25\r<BR>\n" );
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document.write( "               x  = 367.44 say 368\r<BR>\n" );
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document.write( "You will have $25,000 after 368 months ( 30 years & 8 months)<BR>\n" );
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