document.write( "Question 366565: If x=2 to the power y write 2 to the power 2y and 2 to the 2y+1 in terms of x and\r
\n" ); document.write( "\n" ); document.write( "solve the equation 2 to the 2y+1 -5(2 to the y)+2=0
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Algebra.Com's Answer #261233 by amoresroy(361)\"\" \"About 
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If x=2 to the power y write 2 to the power 2y and 2 to the 2y+1 in terms of x and\r
\n" ); document.write( "\n" ); document.write( "x = 2^y\r
\n" ); document.write( "\n" ); document.write( "x^2 = 2^2y\r
\n" ); document.write( "\n" ); document.write( "2x^2 = 2^(2y+1)\r
\n" ); document.write( "\n" ); document.write( "solve the equation 2 to the 2y+1 -5(2 to the y)+2=0\r
\n" ); document.write( "\n" ); document.write( "Express above euation in terms of x\r
\n" ); document.write( "\n" ); document.write( "2x^2 -5x +2 = 0
\n" ); document.write( "Solve for x by factoring method
\n" ); document.write( "(2x-1)(x-2) = 0\r
\n" ); document.write( "\n" ); document.write( "When 2x-1 = 0
\n" ); document.write( " 2x = 1
\n" ); document.write( " x =1/2\r
\n" ); document.write( "\n" ); document.write( "substitute x = 1/2 in equation x = 2^y
\n" ); document.write( " 2^y = 1/2\r
\n" ); document.write( "\n" ); document.write( "Get log of both sides\r
\n" ); document.write( "\n" ); document.write( " log 2^y = log 1/2
\n" ); document.write( " y log 2 = log 1/2
\n" ); document.write( " y = [log 1/2]/log 2\r
\n" ); document.write( "\n" ); document.write( "When x-2 = 0
\n" ); document.write( " x = 2\r
\n" ); document.write( "\n" ); document.write( "substitute x = 2 in equation x = 2^y
\n" ); document.write( " 2^y = 2\r
\n" ); document.write( "\n" ); document.write( "Get log of both sides\r
\n" ); document.write( "\n" ); document.write( " log 2^y = log 2
\n" ); document.write( " y log 2 = log 2
\n" ); document.write( " y = 1
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