document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40722>Question 40722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26121 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle\r<BR>\n" );
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document.write( "Since the area of a rectangle is:\r<BR>\n" );
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document.write( "A = (length)(width) you will need two factors.  One for the width and one for the length.  \r<BR>\n" );
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document.write( "The easiest way is to factor 3x^2 + 5x:\r<BR>\n" );
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document.write( "(x)(3x + 5)  Since (x) is the smallest factor it should be the width and (3x+5) will be the length.\r<BR>\n" );
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document.write( "To check, plug in the factors into the formula for an Area:\r<BR>\n" );
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document.write( "A = (length)(width)<BR>\n" );
document.write( "A = (x)(3x + 5) = 3x^2 + 5x </SPAN>\n" );
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