document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=366547>Question 366547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 41 inches and its area is 91 square inches. find the length of its shortest side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #261209 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=261209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 41 inches and its area is 91 square inches. find the length of its shortest side.\r<BR>\n" );
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document.write( "Let x & y represent the dimensions of the rectangle\r<BR>\n" );
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document.write( "2x + 2y = 41<BR>\n" );
document.write( "    xy  = 91<BR>\n" );
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document.write( "Substitute y = 91/x in  1st equation<BR>\n" );
document.write( "2x + 2(91/x) = 41<BR>\n" );
document.write( "Multiply both sides by x<BR>\n" );
document.write( "2x^2+182+-41x = 0\r<BR>\n" );
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document.write( "Solve for x by factoring<BR>\n" );
document.write( "(2x-13)(x-14)\r<BR>\n" );
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document.write( "2x-13=0<BR>\n" );
document.write( "    x = 6.5\r<BR>\n" );
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document.write( "The shortest side of the rectangle is 6.5 inches<BR>\n" );
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