document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40731>Question 40731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 30/10+Y=  20/10-Y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26120 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 30/10+Y= 20/10-Y\r<BR>\n" );
document.write( "\n" );
document.write( "This problem is asking you to solve for y.  In order to solve for y, you must try to isolate the y to one side of the equation and all other terms to the other side of the equation.\r<BR>\n" );
document.write( "\n" );
document.write( "This problem looks complicated, but it follows the same rules as:\r<BR>\n" );
document.write( "\n" );
document.write( "a/b = c/x  Solve for x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The quickest way to solve for x is to cross-multiply:\r<BR>\n" );
document.write( "\n" );
document.write( "a/b = c/x\r<BR>\n" );
document.write( "\n" );
document.write( "ax = bc\r<BR>\n" );
document.write( "\n" );
document.write( "Divide both sides by \"a\"\r<BR>\n" );
document.write( "\n" );
document.write( "ax/a = bc/a\r<BR>\n" );
document.write( "\n" );
document.write( "x = bc/a\r<BR>\n" );
document.write( "\n" );
document.write( "So, going back to your original problem, treat each term in the fractions as a, b, c, or x.\r<BR>\n" );
document.write( "\n" );
document.write( "30/10+Y= 20/10-Y\r<BR>\n" );
document.write( "\n" );
document.write( "First, cross-multiply:\r<BR>\n" );
document.write( "\n" );
document.write( "30(10-y = 20(10+y)\r<BR>\n" );
document.write( "\n" );
document.write( "Simplify using the distributive property will give you:\r<BR>\n" );
document.write( "\n" );
document.write( "300 - 30y = 200 + 20y\r<BR>\n" );
document.write( "\n" );
document.write( "Solve for \"y\".  Remember, what you do to one side of the equation, you must do to the other side of the equation.\r<BR>\n" );
document.write( "\n" );
document.write( "300 - 200 - 30y = 200 - 200 + 20y\r<BR>\n" );
document.write( "\n" );
document.write( "100 - 30y = 20y\r<BR>\n" );
document.write( "\n" );
document.write( "100 - 30 y + 30y = 20y + 30y\r<BR>\n" );
document.write( "\n" );
document.write( "100 = 50y\r<BR>\n" );
document.write( "\n" );
document.write( "100/50 = 50y/50\r<BR>\n" );
document.write( "\n" );
document.write( "2 = y\r<BR>\n" );
document.write( "\n" );
document.write( "Check to make sure this a true answer, by plugging \"2\" back into the orignial problem.\r<BR>\n" );
document.write( "\n" );
document.write( "30/10+Y= 20/10-Y\r<BR>\n" );
document.write( "\n" );
document.write( "30/10 + 2 = 20/10 - 2\r<BR>\n" );
document.write( "\n" );
document.write( "30/12 = 20/8\r<BR>\n" );
document.write( "\n" );
document.write( "2.5 = 2.5\r<BR>\n" );
document.write( "\n" );
document.write( "The answer checks out!\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );